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Version: 3.4

Procedural DungeonRoom ⏵ Get Doors With

Get Doors With

Class: Room
Category: Room

Description

Returns the door actor shared with the provided room.
Returns null if the provided room is not connected with this.

Node

C++

void GetDoorsWith(const URoom* OtherRoom, TArray<ADoor*> Doors) const

Inputs

NameTypeDescription
TargetRoom Object Reference
Other RoomRoom Object Reference

Outputs

NameTypeDescription
DoorsArray of Door Object References